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Angle c = 90°

side CB = 5
side AB = 13

find the measures of the following items using whatever method you'd like. please show work for full credit

A. measure of angle A to the nearest degree

B. measure of angle B to the nearest degree

C. measure of side AC to the nearest whole number

Angle c = 90° side CB = 5 side AB = 13 find the measures of the following items using-example-1
User Sylver
by
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1 Answer

1 vote
Because you have two of the three measurements needed for the sides, let's do side AC first.

Use the hypotenuse formula: a^+b^2=c^2
Plug in as follows: a^2+5^2=13^2
This is one of the common triangle side trifectas, meaning, whenever you see 5 and 13 as sides, the other side will be 12. Thus, side AC is 12.

To find the other angle, we must use a formula. We already know angle c is 90 degrees. You need to use the formula for law of cosines: a^2=b^2+c^2-2bccosA.

So input: 5^2=12^2+13^2-2(12)(13)cosA.

You get 25=144+169-312cosA. Subtract 144 and 169 on both sides.
Your new equation should look like -288=-312cosA.
Divide both sides by -312 to get about .923. Then use cos^-1(.923) to get angle "a" as 22.62 degrees.

Because we already have angle "c" and "a", add the two then subract by 180.

90+22.62= 112.62. 180-112.62 makes angle b 67.38.
User Alkber
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5.7k points
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