Question

A truck moving at 8.33 m/s accelerates at a constant rate of 42.0 m/s2 for 5.60 seconds. the truck has a final velocity of

Answer 1

Acceleration is 42m/s^2
Antidifferentiated to get the velocity. Added variable c as we do not know if there should be a number there yet.
When time (t) is 0, the velocity is 8.33
Substitute these points into the equation. c = 8.33
Now we have the full equation: v = 42t + 8.33
Now substitute in 5.6 as t. Velocity ends up being 243.53m/s

That is one fast truck.