Question

A professor writes 40 discrete math

a. True
b. False questions. of the statements in these questions, 17 are true. if the questions can be positioned in any order, how many different answer keys are possible?

Answer 1

To find the total number of different answer keys possible, calculate combinations of 40 questions taken 17 at a time using the formula C(40, 17) = 40! / (17! * 23!).

Step-by-step explanation:

The student has asked about the number of different answer keys possible for a discrete math professor who writes 40 questions, out of which 17 are true. To solve this, we use the formula for combinations without repetition since the order of the true and false answers does not matter. The combination formula is given by C(n, k) = n! / (k! * (n-k)!), where 'n' is the total number of questions and 'k' is the number of true questions.

Here, the professor has 40 questions in total and there are 17 true questions. So, we are looking for the combinations of 40 questions taken 17 at a time:

C(40, 17) = 40! / (17! * (40-17)!) = 40! / (17! * 23!)

Calculating this combination would provide the total number of different answer keys possible for the test.

Answer 2

huh what do u mean, is there a possibility of u show the question