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10g of helium (MM=4.0g/mol) occupies a volume of 73L at a temperature of 233k. calculate the pressure of this gas

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PV = nRT (where P = pressure; V = volume; n = number of moles; R = gas constant; T = Temperature)
Moles of He = mass of He ÷ molar mass of He = 10 g ÷ 4 g/mol = 2.5 mol

Now, based on the formula above P = (nRT) ÷ V
P = (2.5 mol × (0.082 L · atm/mol · K) × 233 K) ÷ 73 L ≈ 0.65 atm
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