Question

What are the zeros in the function

f(x)= x^3+x^2-6x

-3,0, and 2

-3,0, and 1

-1,0, and 3

-2,0, and 3

Answer 1

Answer:(3,0)

Explanation:

Edge 2021

Answer 2

`f(x)=x^3+x^2-6x\\\\text{The zeros:}\\\\f(x)=0\to x^3+x^2-6x=0\\\\x(x^2+x-6)=0\\\\x(x^2+3x-2x-6)=0\\\\x[x(x+3)-2(x+3)]=0\\\\x(x+3)(x-2)=0\iff x=0\ \vee\ x+3=0\ \vee\ x-2=0\\\\x=0\ \vee\ x=-3\ \vee\ x=2`

Answer: -3; 0 and 2