Question

What is the internal energy of 3.00 mol of diatomic oxygen gas, O2, at 288 K?

Answer 1

The internal energy of an ideal gas is given by:

`U= (k)/(2)nRT`
where
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
k=3 for monoatomic gases, k=5 for diatomic gases

In this problem, we have n=3.0 mol of a diatomic gas (k=5) at T=288 K. Substituting these numbers into the equation, we find the internal energy of the gas:

`U= (5)/(2)(3.00)(8.31 J/mol K)(288 K)=17950 J`