Question

A sample of ch4o with a mass of 32.0 g contains how many molecules of ch4o?

Answer 1

Answer: A sample of
`CH_4O` will contain
`6.022* 10^(23)` number of molecules

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}`

Given mass of
`CH_4O` = 32.0 g

Molar mass of
`CH_4O` = 32 g/mol

Putting values in above equation, we get:

`\text{Moles of }CH_4O=(32.0g)/(32g/mol)=1mol`

According to mole concept:

1 mole of a compound contains
`6.022* 10^(23)` number of molecules

Hence, a sample of
`CH_4O` will contain
`6.022* 10^(23)` number of molecules

Answer 2

According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).
1 mole of CH4O contains 32 g
therefore; 32 g of CH4O is equivalent to 1 mole;
Hence; 32 grams of CH4O contains 6.022 ×10^23 molecules.