Question

A force of 3600 N is exerted on a piston that has an area of 0.030 m2. What force is exerted on a second piston that has an area of 0.015 m2?

Answer 1

18,000 N

Step-by-step explanation:

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Answer 2

For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:

`p_1 = p_2`
which becomes

`(F_1)/(A_1)= (F_2)/(A_2)`
where

`F_1=3600 N` is the force on the first piston

`A_1=0.030 m^2` is the area of the first piston

`F_2` is the force on the second piston

`A_2=0.015 m^2` is the area of the second piston

If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:

`F_2=F_1 (A_2)/(A_1)=(3600 N) (0.015 m^2)/(0.030 m^2)= 1800 N`