Question

What is the true solution to the logarithmic equation below? log4[log4(2x)]=1

a. x=2
b. x=8
c. x=64
d. x=128

Answer 1

To solve this problem, you have:
1. You have the following logarithmic expression log4[log4(2x)]=1, therefore:
log4[log4(2x)]=1
4^log4[log4(2x)]=4^1
2. By definition, a^log(x)=x, then:
log4(2x)=4
4^log4(2x)=4^4
2x=4^4
x=256/2
x=128
Therefore, the answer is the option d: d. x=128