Answer:
The correct answer is B
Explanation:
Step 1
The first step in identifying the graph of the function is to determine where the vertical asymptotes occur. The vertical asymptotes occurs where the expression in the numerator is zero,
.
The next step is to calculate the
intercept. The
intercept occurs where
. We determine intercept as shown below,
![f(x)=(2x)/(x^2-1)=0\\ \implies 2x=0\\\\\implies x=0](https://img.qammunity.org/2019/formulas/mathematics/high-school/5xmlieb7h3ardgzjic6ogxprlit9yodse5.png)
Step 2
The next step is to find the
intercept. The
intercept occurs when
. We determine the
intercept as shown below,
The
intercept occurs at
![y=0.](https://img.qammunity.org/2019/formulas/mathematics/high-school/d45u5nsw4p3fojmp3z9e2fj35zkyp7h2sc.png)
Step 3
We now investigate the behavior of the function for different values of
. We can tell that
,
![x>1,f(x)>0\\0<x<2,f(x)<0\\-1<x<0,f(x)>0\\x<-2,f(x)<0.](https://img.qammunity.org/2019/formulas/mathematics/high-school/scfrvoaw399xmdwtmi6oyju5is121zkazz.png)
Step 4
The only graph that has vertical asymptotes at
and that crosses goes through
and meets all the conditions in Step 3 is the second graph B.