Without knowing what the possible answer choices are, perhaps this is one of them:
![\tan^2\frac a2=(\sin^2\frac a2)/(\cos^2\frac a2)=\frac{\frac{1-\cos a}2}{\frac{1+\cos a}2}=(1-\cos a)/(1+\cos a)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/4y5orkv9pk7dka7wfa1fbncxb8r4yze9x4.png)
We can rewrite this in several ways, but one that should immediately occur to you is to consider writing the denominator in terms of
![\sin a](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7luwtqzof38t0m2sacfh67fg3ovuu0qrm3.png)
:
![(1-\cos a)/(1+\cos a)\cdot(1-\cos a)/(1-\cos a)=(1-2\cos a+\cos^2a)/(1-\cos^2a)=(1-2\cos a+\cos^2a)/(\sin^2a)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/eo587geajowg5oawdpx1p6ylanl8jkkkpw.png)
We can further write this in terms of the reciprocal functions,
![\frac1{\sin^2a}-(2\cos a)/(\sin^2a)+(\cos^2a)/(\sin^2a)=\csc^2a-2\csc a\cot a+\cot^2a](https://img.qammunity.org/2019/formulas/mathematics/middle-school/49rzutkmanlc1kxlpdcqqnkxir6n8kjiqe.png)
and so on...