Question

What is the complete ionic equation for the reaction 2koh(aq) + h2so4(aq) 2h2o(l) + k2so4(aq)?

Answer 1

To find the complete ionic equation:

Consider:

Equation for the dissociation of the strong base in aqueous solution:

KOH (aq)------> K⁺(aq) + OH⁻(aq)

Equation for the dissociation of the strong acid in aqueous solution:

H₂SO₄(aq)------>2H⁺(aq) + SO₄²⁻(aq)

On the product' side, potassium sulfate that is a ionic compound:

K₂SO₄(aq)------>2K⁺ +SO₄²⁻

Water, a covalent compound:

So net balanced equation will be:

K⁺(aq) + OH⁻(aq) +2H⁺(aq) + SO₄²⁻(aq)------>2K⁺ + SO₄²⁻ +H₂O(l)

Net ionic equation by eliminating the spectator ions:

OH⁻(aq) +2H⁺(aq)-------->H₂O(l)

Answer 2

Answer : The complete ionic equation in separated aqueous solution will be,

`2K^+(aq)+2OH^(-)(aq)+2H^(+)(aq)+SO_4^(2-)(aq)\rightarrow 2K^+(aq)+SO_4^(2-)(aq)+H_2O(l)`

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

`2KOH(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+K_2SO_4(s)`

The complete ionic equation in separated aqueous solution will be,

`2K^+(aq)+2OH^(-)(aq)+2H^(+)(aq)+SO_4^(2-)(aq)\rightarrow 2K^+(aq)+SO_4^(2-)(aq)+H_2O(l)`