Answer:
axis of symmetry at x=6
Explanation:
![y=-3(x-6)^2+5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lc9qbhkcgpszoy0qx8nefly74ipg94z73v.png)
The given equation is in vertex form
![y=a(x-h)^2+k](https://img.qammunity.org/2019/formulas/mathematics/college/tbh7747l327y3m70wjz077h6ij0n8qkom0.png)
(h,k) is the vertex
Compare the vertex form of the equation with the given equation.
![y=-3(x-6)^2+5](https://img.qammunity.org/2019/formulas/mathematics/middle-school/lc9qbhkcgpszoy0qx8nefly74ipg94z73v.png)
The value of h = 6 and the value of k = 5
So vertex is (6,5)
Axis of symmetry lies at the x coordinate of the vertex
x coordinate of the vertex is 6
So axis of symmetry at x=6