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A recent poll of 80 randomly selected Californians showed that 38% ( = 0.38) believe they are doing all that they can to conserve water. The state government would like to know, within a 99% confidence level, the margin of error for this poll. (99% confidence level z*-score of 2.58) Remember, the margin of error, E, can be determined using the formula E = z*√p(1-p) / n. To the nearest whole percent, the margin of error for the poll is...?

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To the nearest whole percent the margin error for this poll would be 38% ⁺/₋ 14%. If you want me to explain feel free to ask!
User Jakubka
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