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What is the equation of the line perpendicular to y = 2/3 x + 1 that passes through the point (12, –6)?

1 Answer

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y = 2/3 x + 1 slope = 2/3
perpendicular line, slope is opposite and reciprocal so slope = -3/2
passes through the point (12, –6)

y + 6 = -3/2 (x - 12)
y + 6 = -3/2 x + 18
y = -3/2 x + 12

Answer
y = -3/2 x + 12
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