Question

PLEASE HELP LAST QUESTION The figure below shows triangle ABC on the coordinate plane.

Write the coordinates of the vertices of a triangle A'B'C' that results from a translation of triangle ABC two units to the right and four units down .

A'(
a0,_____ 
a1_____)

B'(
a2,____ 
a3____)

C'(
a4,____ 
a5____)

Answer 1

B is (0,1)
A is (4,-6)
C is (-2, -2)

Answer 2

Answer: A'(4,-6) , B'(0,1), C'(-2,-2)

Explanation:

From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)

If a translation is applied on ΔABC two units to the right and four units down to create ΔA'B'C'.

Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule

`(x,y)\rightarrow(x+2,y-4)`

Now,
`A(2,-2)\rightarrow A'(2+2,-2-4)=A'(4,-6)`

`B(-2,5)\rightarrow B'(-2+2,5-4)=B'(0,1)`

and
`C(-4,2)\rightarrow C'(-4+2,2-4)=C'(-2,-2)`