Question

What is the value of this expression when m=3 and n=-5 (6m^-1n^0)^-3

Answer 1

`(1)/(8)`

Explanation:

Given expression is,

`(6m^(-1)n^0)^(-3)`

`=(6m^(-1))^(-3)` (
`a^0 =1` )

`=6^(-3) (m^(-1))^(-3)` (
`(ab)^m=a^mb^m` )

`=6^(-3) m^(-1* -3)` (
`(a^m)^n=a^(mn)` )

`=6^(-3) m^3`

`=(m^3)/(6^3)` (
`a^m=(1)/(a^(-m))` )

`=(m^3)/(216)`

We have, m = 3

`=(3^3)/(216)`

`=(27)/(216)`

`=(1)/(8)`

Answer 2

this is

(6(3)^-1 (-5)^0)^-3

= (6/3 * 1)^-3

= (2)^-3

= 1/8 Answer