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With what minimum speed must a ball be thrown straight up in order to reach a height of 22 m above the launch position?

User Elyse
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User Affian
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Vi=?Vf=0h=22mg= -9.8m/s/s (upward negative)

equation of motion used is:Vf^2 -Vi^2 = 2gh
=> Vi = 20.76 m/s



User Alan Barber
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