Question

Write an equation for the line parallel to the line

−x−8y=3
−x−8y=3
through the point
(−1,4)

Answer 1

Parallel means "same slope" so the first thing needed to solve is to find the slope of -x - 8y = 3. The easiest way to do this is to put it into slope-intercept form (y = mx + b).

- x - 8y = 3
- 8y = x + 3 Add "x" to both sides
y =
`(-1)/(8)x` + 3 Divide both sides by "-8"
Slope =
`(-1)/(8)`

Next, input the slope and point into the point-slope form (y - y1 = m(x - x1))

y - 4 =
`(-1)/(8)`(x + 1)
y - 4 =
`(-1)/(8)x` -
`(1)/(8)`
y =
`(-1)/(8)x` -
`(1)/(8)` + 4
y =
`(-1)/(8)x` +
`(31)/(8)`