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One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin c, c6h8o6). given that one cup

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The question is incomplete. Complete question is read as:
'One cup of fresh orange juice contains 115 mg of ascorbic acid (vitamin C, C6H8O6). Given that one cup = 218.0 mL calculate the molarity of vitamin C in organic juice.'
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Answer:
Given: weight of solute (ascorbic acid) = 115 mg = 0.115 g
Volume of solution = 218.0 mL = 0.218 L
Molecular weight of ascorbic acid = 176.12 g/mol.

Now, Molarity =
\frac{\text{weight of solute(g)}}{\text{Molecular weight X Vol. of solution(l)}}
=
\frac{\text{0.115}}{\text{176.12 X 0.218}}
= 0.002995 mol/dm3

Answer: Molarity of solution =
0.002995 mol/dm3

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