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Find the value of x to the nearest tenth.

Find the value of x to the nearest tenth.-example-1

2 Answers

2 votes

Answer:

The value of x is 11.

Explanation:

From the figure it is clear that the given triangle is a right angled triangle. The length of hypotenuse is x units , an angle 35° and adjacent side is 9 units.

Using trigonometric ratios, in a right angled triangle,


\cos \theta = (adjacent)/(hypotenuse)

Substitute θ=35, adjacent = 9, hypotenuse =x in the above equation.


\cos 35=(9)/(x)


0.819=(9)/(x)

Multiply both sides by x.


0.819x=9

Divide both sides by 0.819.


x=(9)/(0.819)


x=10.989\approx 11

Therefore the value of x is 11.

User Glenn Ferrie
by
6.5k points
6 votes
cos(angle) = Adjacent Leg / Hypotenuse

cos(35) = 9 / x

x = 9 / cos(35)

x = 10.99

Rounded to nearest tenth = 11.0
User Match
by
5.9k points