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How many grams of fluorine are needed to react with 8.5g of phosphorus?

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Step 1: write the equation:

P₄(s) + 6F₂(g) → 4PF₃(g)


Step 2: Molar mass of P₄ = 30.97 g/mol × 4 = 123.88 g/mol


Step 3: Number of moles of phosphorus

n = m/M

n = 8.5 g/123.88g/mol

n = 0.07 moles


Step 4: 0.07 × 12 = 0.84 moles of fluorine.

Fluorine is diatomic gas so we multiplied the number of moles by 12.


Step 5: To find the mass of fluorine we multiply the number of moles with the molar mass.

Mass of fluorine = 0.84 × 228

= 191.52 grams.

User Simon Miller
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