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The times it took for 35 loggerhead sea turtle eggs to hatch in a simple random sample are normally distributed, with a mean of 50 days and a standard deviation of 2 days. Assuming a 95% confidence level (95% confidence level = z-score of 1.96), what is the margin of error for the population mean?

Remember, the margin of error, ME, can be determined using the formula (the formula is in the pic)

0.06
0.11
0.34
0.66

The times it took for 35 loggerhead sea turtle eggs to hatch in a simple random sample-example-1

1 Answer

2 votes
0.06 so ME equals 0.06 of intercourse wrong I apologize
User Mansoor Elahi
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