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SOMEONE PLZ ANSWER GIVING 45 POINTS FOR THIS QUESTION! A fair decimal die is tossed five times. Find the probability of obtaining an odd number of even digits.

User Settheline
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Well, an even decimal die has probability 0.5 of rolling even and 0.5 of rolling odd.

The chances of rolling exactly one even number on five rolls is P(even)⋅(P(odd))4=0.5⋅0.54=0.55=132." role="presentation">P(even)⋅(P(odd))4=0.5⋅0.54=0.55=132.P(even)⋅(P(odd))4=0.5⋅0.54=0.55=132.

The chances of rolling exactly three even numbers on five rolls is (P(even))3⋅(P(odd))2=0.53⋅0.52=0.55=132" role="presentation">(P(even))3⋅(P(odd))2=0.53⋅0.52=0.55=132(P(even))3⋅(P(odd))2=0.53⋅0.52=0.55=132.

The chances of rolling exactly five even numbers on five rolls is (P(even))5=0.55=132" role="presentation">(P(even))5=0.55=132(P(even))5=0.55=132.

Further, the probability of independent events is the sum of their probabilities, so the probability of rolling an odd number of even numbers is 332" role="presentation">332


User Cody Guldner
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