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22 votes
22 votes
What is the value of (x+y)^2 when x=2 and y= -4?

User Rahatur
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1 Answer

9 votes
9 votes

Answer: 20

Step-by-step explanation:

Everything within the parenthesis gets an exponent of two, so you should have (x^2+y^2).

After this, you plug in the 'x' and 'y' given, so the next part should look like (2^2+(-4)^2)

After step 2, do 2*2 and -4*-4 (exponents ask you to multiply numbers by a specific amount. In this case, both numbers are multiplied by themselves 2 times).

A negative times a negative is a positive, so -4^2 or -4*-4 is 16. 2^2 or 2*2 is simply 4.

Add 4 and 16 together to get your final answer of 20.

Hope this helps!

User Tourki
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2.5k points