The first thing to do is find the percentage of number of players with no defects.
For this, we make the following rule of three:
500 --------> 100%
496 --------> x
Clearing x we have:
x = (496/500) * (100)
x = 99.2%
Then, for 2000 video players we have:
(2000) * (0.992) = 1984
Answer:
The number of players in the shipment that are likely to have no defects are:
1984