The area of the regular hexagon is:
A1 = 2.60 * (8) ^ 2
A1 = 166.4 in ^ 2
The area of the square is:
A2 = (8) * (8)
A2 = 64 in ^ 2
The area of the triangle is:
A3 = root ((s-a) * (s-b) * (s-c) * (s))
Where,
s = (a + b + c) / 2
s = (8 + 8 + 8) / 2
s = 24/2
s = 12
A3 = root ((12-8) * (12-8) * (12-8) * (12))
A3 = 27.71
Then, the area of the pattern is:
A = A1 + 6 * A2 + 6 * A3
Substituting:
A = 166.4 + 6 * (64) + 6 * (27.71)
A = 716.6 in ^ 2
Answer:
C.
716.6 in.²