115k views
0 votes
A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y = –0.04x2+ 8.3x + 4.3, where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land?

User PomPom
by
4.6k points

1 Answer

6 votes
For this case we have the following equation:
y = -0.04x2 + 8.3x + 4.3
We must match the equation to zero:
-0.04x2 + 8.3x + 4.3 = 0
From here, we must find the roots of the polynomial.
Using the resolver, we have the roots are:
x1 = -0.52
x2 = 208,017
We take the positive root because it is a distance.
Answer:
the rocket will land 208.017 m far horizontally from its starting point
User Chris Weber
by
5.8k points