Answer:
The answer is: 'no solution'
Explanation:
The given equation is:
![3√(5x-4)=3√(7x+8)](https://img.qammunity.org/2019/formulas/mathematics/college/pjsx5tr33aa3npl400q555ovjvlrutjwsn.png)
Dividing both sides of the equation by 3, we will get.....
![√(5x-4)=√(7x+8)](https://img.qammunity.org/2019/formulas/mathematics/college/i3jc208raq6hd09erki5hb01nan638tatr.png)
Taking square on both sides.....
![(√(5x-4))^2=(√(7x+8))^2\\ \\ 5x-4=7x+8\\ \\ 5x-7x=8+4\\ \\ -2x=12\\ \\ x=(12)/(-2)=-6](https://img.qammunity.org/2019/formulas/mathematics/college/c51may4eiss2cgny1atxqc5l6az6tjtbjy.png)
Plugging this
back to the given equation......
![3√(5(-6)-4)=3√(7(-6)+8)\\ \\ 3√(-34)=3√(-34)](https://img.qammunity.org/2019/formulas/mathematics/college/yqqcxdge3ik5eal7y8shwhpl8lcpzzq0bo.png)
As we are getting a negative number inside the square root, so the equation becomes imaginary. Thus
is a restricted value.
Hence, there is 'no solution' for this equation.