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What is the m∠ACB? 10° 50° 90° 180°

What is the m∠ACB? 10° 50° 90° 180°-example-1
User Tjfdfs
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2 Answers

1 vote

Answer:

50°

Explanation:

90 + 4x+ 7x - 20(+20) = 180 + 20

4x + 7x = 200 - 90

4x + 7x = 110

11x/11 = 110/11

X = 10

m∠ACB = 7x - 20 = 7(10) - 20 = 50

User Karim Tarek
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8.0k points
2 votes
The total sum of angles in a triangle is 180, thus the value of ∠ACB will be obtained as follows:
Given that the triangle is a right triangle, the sum of angles will be:
(4x)°+(7x-20)°+90=180
simplifying and solving for x we get:
4x+7x-20+90=180
11x=180+20-90
11x=110
dividing both sides by 11 we get:
(11x)/11=110/11
this gives us
x=10°
Thus substituting the value of x in:
∠ACB=(7x-20)°
=(7*10-20)
=70-20
=50°

Answer: 50°
User Herzi
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7.4k points