Question

Find the sum 5/m^2n^2 + m/n

Answer 1

Since the denominators of the two fractions are different, we need to make them same and then add the two fractions


`(5)/( m^(2) n^(2) ) + (m)/(n) \\ \\`

LCM is m²n² . So we can write:


`(5)/( m^(2) n^(2) ) + (m)/(n) \\ \\ = (5)/( m^(2) n^(2) )+ (m(m^(2)n) )/( n(m^(2) n) ) \\ \\ = (5)/( m^(2) n^(2) )+(m^(3)n )/( m^(2) n^(2) ) \\ \\ = (5+m^(3)n)/(m^(2) n^(2) )`