Hello!
To find the surface area of a cylinder you use the equation
![SA = 2 \pi rh+ 2 \pi r^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/qz3wvd9jiyoextsmtqur9j2b7s2mvl0vu2.png)
SA is surface area
r is radius
h is height
Put in the values you know
![SA = 2 \pi (38)(123) + 2 \pi * 38^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ufj8xuhiy60teaok9knwo6cmi809rmmlbi.png)
Square the number
![SA = 2 \pi (38)(123) + 2 \pi * 1444](https://img.qammunity.org/2019/formulas/mathematics/high-school/hs6jzl85j2qwuj33u5tfc579u8r0cc3myo.png)
Multiply 38 and 123
![SA = 2 \pi * 4674 + 2 \pi * 1444](https://img.qammunity.org/2019/formulas/mathematics/high-school/lg2qaxwwfwhztzb9e6u7gev1t5nqwaavx7.png)
Multiply 2 and 4674
![SA = 9348 \pi + 2 \pi * 1444](https://img.qammunity.org/2019/formulas/mathematics/high-school/iqqs6kj34u61pl02eujw45zugruytoq46f.png)
Multiply the 2 and 1444
![SA = 9348 \pi + 2888 \pi](https://img.qammunity.org/2019/formulas/mathematics/high-school/tdm9kdjqxzo20kecaeyvsa15673ujbgviw.png)
Add
![SA = 12236 \pi = 38440.53](https://img.qammunity.org/2019/formulas/mathematics/high-school/9vi21w0mzq71z107ef6mw49hjhvsr7i4kf.png)
The answer is 12236 pi or about 38440.53
Hope this helps!