Question

How much grams of Mg(OH)2 is formed if 103g of H2O reacted? (Round answer to the nearest tenths)

Mg2Si+ 4H2O———-> 2Mg(OH)2 + SiH4
(Improvised arrow above
Not an inequality sign)

Answer 1

Answer:
117 g of Mg(OH)₂

Solution:
The equation is as follow,

Mg₂Si + 4 H₂O → 2 Mg(OH)₂ + SiH₄

According to equation,

72 g (4 moles) H₂O produces = 116.64 g (2 mole) Mg(OH)₂
So,
103 g of H₂O will produce = X g of Mg(OH)₂

Solving for X,
X = (116.64 g × 103 g) ÷ 72 g

X = 116.86 g ≈ 117 g of Mg(OH)₂