Answer:
117 g of Mg(OH)₂
Solution:
The equation is as follow,
Mg₂Si + 4 H₂O → 2 Mg(OH)₂ + SiH₄
According to equation,
72 g (4 moles) H₂O produces = 116.64 g (2 mole) Mg(OH)₂
So,
103 g of H₂O will produce = X g of Mg(OH)₂
Solving for X,
X = (116.64 g × 103 g) ÷ 72 g
X = 116.86 g ≈ 117 g of Mg(OH)₂