2 Answers

Dimitar Mirchev · Answer 1 · 2019-08-11T21:01:45+0000

The surface area of the prism is the sum of surface areas of 3 rectangles and 2 triangles.

The surface area of rectangles are

$10*5=50\;cm^2,10*5=50\;cm^2,10*6=60\;cm^2$ .

The sum is

$50\;cm^2+50\;cm^2+60\;cm^2 =160\;cm^2$ .

The are of each triangle is
$(1)/(2) 6*4\;cm^2$ .

The sum of areas of 2 triangles is
$2*(1)/(2) 6*4\;cm^2 =24\;cm^2$ .

The surface area of the prism is

$160\;cm^2+24\;cm^2=184\;cm^2$ .

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