A stone that starts at rest free falls for 7.0 s. How far does the stone fall in this time?

asked Apr 25, 2019 43.1k views

3 votes

7.0k points

Please log in or register to add a comment.

5 votes

Gravitational acceleration is approx 9.8 m/s
Time is 7s

a=9.8 m/s
t=7s

a = d/t^2

therefore:

d = a * t^2

d = 9.8 * 7^2

d = 9.8 * 49

d = 480.2 [m]

Kathryn answered Apr 30, 2019

7.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.6m questions

10.1m answers