Question

Someone please help me??

Answer 1

The standard equation of a circle with centre (xc,yc) and radius R is given by


`(x-x_c)^2+(y-y_c)^2=R^2`

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore


`(x-x_c)^2+(y-y_c)^2=R^2`

`(x-4)^2+(y-(-3))^2=2.5^2`

`(x-4)^2+(y+3)^2=2.5^2` or
(x-4)^2+(y+3)^2=6.25