Question

How many moles of nh3 can he produced from the reaction of 38 g of n2

Answer 1

N₂ + 3 H₂ → 2 NH₃

number of moles of N₂ = 38 g / 28 g/mol = 1.357 mol

1 mole of N₂ gives 2 moles of NH₃
1.357 mol of N₂ will give ?? mole NH₃

= 2 x 1.357 = 2.7 mol NH₃