Question

Given a mean of 61.2 and a standard deviation of 21.4 what is the z score of the value 90 rounded to the nearest tenth?

Answer 1

1.35

Explanation:

Answer 2

The z-score of 90 is 1.35

Explanation:

The z-score is calculated using the formula:

`z = (x - \mu)/( \sigma)`

From the question, it was given that the mean is

`\mu = 61.2`

and the standard deviation is

`\sigma = 21.4`

and x=90.

We substitute the given values to obtain:

`z = (90 - 61.2)/(21.4)`

`z = (28.8)/(21.4) = 1.35`