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How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution react with excess aluminum metal? Show all of the work needed to solve this
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How many grams of iron metal do you expect to be produced when 245 grams of an 80.5 percent by mass iron (II) nitrate solution react with excess aluminum metal? Show all of the work needed to solve this problem.

2Al (s) + 3Fe(NO3)2 (aq) yields 3Fe (s) + 2Al(NO3)3 (aq)

User Mkalafut
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80.5% x 245 / 180 = 1,096 mol Fe(NO3)2
=> 1,096 x 56 = 61,32 gram iron metal
User Tom Elias
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