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This system has one solution.

{y=−2x+4y
{=x2+4x+13

What is the y-coordinate of the solution?

Enter your answer in the box. y =[]

2 Answers

4 votes
Hello there!
I have just taken the test on this answer and I got 10...
I hope this helps!!
User Samvv
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4 votes

Answer:

The y-coordinate of the solution is, 10

Explanation:

Given the system of equation:


y = -2x+4 ....[1]


y=x^2+4x+13 ....[2]

Equate the equation [1] and [2] we have;


-2x+4 = x^2+4x+13

Add 2x to both sides of an equation:


4 = x^2+6x+13

Subtract 4 from both sides we have;


0= x^2+6x+9

or


x^2+6x+9=0

Using perfect square:


(x+a)^2 = x^2+2ax+a^2

⇒We can write the equation as:


x^2+2 \cdot 3x+3^2=0

then;


(x+3)^2 = 0


x+3 = 0

Subtract 3 from both sides we have;

x = -3

Substitute value of x in [1] we have;


y = -2(-3)+4


y =6+4=10

Solution for the given system of equation = (-3, 10)

Therefore, the y-coordinate of the solution is, 10

User Muxecoid
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