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3 votes
Find all solutions for a triangle with C=17%, a=10, and c=11. Round to the nearest tenth.

User Mkrause
by
6.8k points

2 Answers

5 votes
I feel like the correct answer is C
User Fxnn
by
7.2k points
4 votes

I'll assume that's C=17 degrees, a=10, c=11.

Law of sines says


(a)/(\sin A) = (c)/(\sin C)


\sin A = (a)/(c) \sin C


\sin A = (10)/(11) \sin 17^\circ=0.265792


A = \arcsin 0.265792 = 15.414^\circ \textrm{ or }164.586^\circ

We get supplementary angles for the inverse sine.

We can ignore the larger one because 164.5+17>180 so not a valid traingle.


A= 15.414^\circ, \quad B = 180^\circ - A - C = 147.586^\circ


b = (c\sin B)/(\sin C)= (11 \sin 147.586^\circ)/(\sin 17^\circ) = 20.1674

Rounding,

Answer: A=15.4°, B=147.6°, b=20.2

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