Question

A man weighing 680N and a woman weighing 500N have the same momentum. What is the ratio of the man's kinetic energy Km to that of the woman Kw?

A cardinal (Richmondena cardinalis) of mass 3.60

Answer 1

To find the ratio of the man's kinetic energy (Km) to that of the woman's kinetic energy (Kw), we can set up an equation using their momentum. The ratio is 1.36:1.

Step-by-step explanation:

To find the ratio of the man's kinetic energy (Km) to that of the woman's kinetic energy (Kw), we first need to determine their speeds. We know that momentum is equal to mass times velocity, and since their momenta are equal, we can set up the equation:

man's momentum = woman's momentum

(man's mass)(man's velocity) = (woman's mass)(woman's velocity)

Using the given weights and assuming both are moving in a straight line:

(680N)(v) = (500N)(v)

Dividing both sides by v, we get:

680N = 500N

Therefore, the ratio of the man's kinetic energy to that of the woman's is 680N:500N, or 1.36:1.

Answer 2

`(K_m)/(K_w)=0.734`

Step-by-step explanation:

given,

weight of the man = 680 N

weight of the woman = 500 N

mass of man =
`(680)/(9.8)`

M_m = 69.4 Kg

mass of woman

=
`(500)/(9.8)`

M_w = 51 Kg

ratio of man's kinetic energy Km to that of the woman Kw

`(K_m)/(K_w)=((P_m^2)/(2M_m))/((P_w^2)/(2M_w))`

momentum is same

`(K_m)/(K_w)=(2M_w)/(2M_m)`

`(K_m)/(K_w)=(M_w)/(M_m)`

`(K_m)/(K_w)=(51)/(69.4)`

`(K_m)/(K_w)=0.734`