Question

Cosmic rays are charged particles, such as electrons and protons, traveling at near the speed of light. If the mass of a proton is approximately 1833 times the mass of an electron, how much more energy does the more energetic particle have than the less energetic particle? The energy of a cosmic ray particle can be found using Einstein's formula E = mc^2.

Answer 1

Cosmic rays are charged particles that travel at near the speed of light. The energy of a more energetic particle is 1833 times greater than that of a less energetic particle.

Step-by-step explanation:

Cosmic rays are charged particles, such as electrons and protons, that travel at near the speed of light. The energy of a particle can be found using Einstein's formula E = mc^2, where E is the energy, m is the mass, and c is the speed of light.

In this case, the mass of a proton is approximately 1833 times the mass of an electron. So, if we consider a more energetic particle as a proton and a less energetic particle as an electron, the more energetic particle would have 1833 times more energy than the less energetic particle.

Answer 2

1833

Step-by-step explanation:

c = Speed of light =
`3* 10^8\ m/s`

Mass of proton =
`m_p`

The mass of proton is given by

`m_p=1833m_e`

Energy of proton is given by

`E_p=m_pc^2`

Energy of electron is given by

`E_e=m_ec^2`

Divide the equations

`(E_p)/(E_e)=(m_pc^2)/(m_ec^2)\\\Rightarrow (E_p)/(E_e)=(1833m_ec^2)/(m_ec^2)\\\Rightarrow (E_p)/(E_e)=1833\\\Rightarrow E_p=1833E_e`

The particle will be 1833 times the less energetic particle