Question

Coming to the bottom of a mountain, a skier moving with speed v collides with a barrier and is brought to a stop in an amount of time t. Over the course of the impact, the skier experienced an average net force F from the barrier. If the skier\'s initial velocity had been the same (v), but the time of impact to come to a full stop had been four times as long (4t), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) F/4b)Fc)4Fd) F/2e)2FIf the time of impact to come to a full stop had been the same (t), but the skier\'s initial velocity had been half as much (v / 2), what would have been the average net force exerted on the skier during the collision? The average net force would have been...a) 4Fb)Fc)2Fd) F/4e)F/2

Answer 1

The average net force exerted on a skier during a collision can be calculated using Newton's second law. If the time of impact is four times longer or the initial velocity is halved, the average net force changes accordingly.

Step-by-step explanation:

The average net force exerted on a skier during a collision can be determined using Newton's second law, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

In this case, the skier experiences an average net force (F) over a given time interval (t) to come to a stop.

If the skier's initial velocity (v) remains the same, but the time of impact to come to a full stop becomes four times as long (4t), the average net force exerted on the skier during the collision would be one-fourth of the original force, F/4.

Similarly, if the time of impact to come to a full stop remains the same (t), but the skier's initial velocity is halved (v/2), the average net force exerted on the skier during the collision would be half of the original force, F/2.

Answer 2

Step-by-step explanation:

Impulse of a force is measured by force x time or F X t

Impulse also equals change in momentum or

F x t = m v₂ - m v₁

The given case is as follows

in the first case

F x t = mv - o = mv

F = mv / t

in the second case

F₁ x 4 t = mv

F₁ = 1/4 x mv /t

F₁ = F / 4

option a) is correct .

iii )

In the last case

F₂ X t = m v/2 -0

F₂ = 1/2 x mv / t

= 1/2 x F

F₂ = F/2

Option e ) is correct.