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A thin, metallic spherical shell of radius 0.227 m has a total charge of 6.03 × 10 − 6 C placed on it.

A point charge of 1.15 × 10 − 6 C is placed at the center of the shell.

What is the electric field magnitude E a distance 0.735 m from the center of the spherical shell?

User Asif Rehan
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1 Answer

2 votes

Answer:

Step-by-step explanation:

Given

radius
r=0.227 m

Charge on surface
Q=6.03* 10^(-6) C

Point Charge inside sphere
q=1.15* 10^(-6) C

Electric Field at
r=0.735 m

Treating Surface charge as Point charge and applying Gauss law


E_(total)A=(q_(enclosed))/(\epsilon _0)

where A=surface area up to distance r


E_(total)=(Q+q)/(4\pi r^2)


E_(total)=(6.03* 10^(-6)+1.15* 10^(-6))/(4\pi (0.735)^2* 8.85* 10^(-12))


E_(total)=1.194* 10^(5) N/C

User Rutrus
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