Answer: This a redoc reaction.
The total ionic equation in separated aqueous solution will be,
![2H^+(aq)+2O^(-)(aq)+Mg^(2+)(aq)+SO_3^(2-)(aq)\rightarrow Mg^(2+)(aq)+SO_4^(2-)(aq)+H_2O(l)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/774hkhddaqo06n2021fm48i3fsxctwg13m.png)
Explanation :
The given reaction is a redox reaction in which the oxygen shows reduction and sulfur shows oxidation reaction.
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The given balanced ionic equation will be,
![H_2O_2(aq)+MgSO_3(aq)\rightarrow MgSO_4(aq)+H_2O(l)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/3hmjl8tw0u9kvc58y9pq45kvwr56bqg14t.png)
The total ionic equation in separated aqueous solution will be,
![2H^+(aq)+2O^(-)(aq)+Mg^(2+)(aq)+SO_3^(2-)(aq)\rightarrow Mg^(2+)(aq)+SO_4^(2-)(aq)+H_2O(l)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/774hkhddaqo06n2021fm48i3fsxctwg13m.png)