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What constant acceleration is needed to accelerate a baseball from 6 feet/sec to 116 feet/sec in 2 seconds?

a. 27.5 feet/sec
b. 29 feet /sec
c. 58 feet /sec2
d. 55 feet /sec2

User Fabulous
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1 Answer

6 votes

Answer:

d. 55 feet /sec^2

Explanation:

Average acceleration is ...

a = ∆v/∆t = (116 ft/s -6 ft/s)/(2 s)

= 110/2 ft/s^2 = 55 ft/s^2

User Robert Ros
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8.3k points