Question

One end of a plastic pipe is capped and the other end is open. The pipe stands on the capped end in a magnetic field of 0.030 T that makes an angle of 10° with the vertical. The pipe has an inside diameter of 5 cm. What is the flux through the plastic of the pipe?

Answer 1

magnetic flux = 0.579 ×
`10^(-5)` Weber

Step-by-step explanation:

given data

magnetic field B = 0.030 T

angle ∅ = 10°

diameter d = 5 cm

to find out

flux through the plastic of the pipe

solution

we get here magnetic flux that is express as

magnetic flux = magnetic field × Area × cos∅ ..............1

put here value we get

magnetic flux = 0.030 ×
`(\pi)/(4) d^2` × cos10

magnetic flux = 0.030 ×
`(\pi)/(4) 0.05^2` × cos10

magnetic flux = 0.030 × 1.9634 ×
`10^(-3)`× 0.984

magnetic flux = 0.579 ×
`10^(-5)` Weber