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PLZ HELP ME ITS MY LAST QUESTION I GOT LIKE 6 MIN LEFT

A 77kg diver jumps from a 8.18m high diving platform. Why is the speed in m/s of the diver right before she hits the water?

User Zorji
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1 Answer

4 votes

Answer:

12.7m/s

Step-by-step explanation:

Given parameters:

Mass of the diver = 77kg

Height = 8.18m

Unknown:

Speed of the diver before hitting the water = ?

Solution:

The speed of the diver before hitting the water is the final velocity.

To solve this problem, we use the expression below;

v² = u² + 2gH

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

H is the height

Now insert the parameters and solve;

v² = 0² + 2 x 9.8 x 8.18

v² = 160.328

v = 12.7m/s

User Makevoid
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4.4k points