Question

ΔDOG has coordinates D (3, 2), O (2, −4) and G (−1, −1). A translation maps point D to D' (2, 4). Find the coordinates of O' and G' under this translation.

O' (−1, 1); G' (1, −2)
O' (3, 0); G' (−1, −1)
O' (0, −3); G' (−3, 0)
O' (1, −2); G' (−2, 1)

Answer 1

see explanation

Explanation:

Given D(3, 2 ) → D'(2, 4 )

The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is

(x, y ) → (x - 1, y + 2 )

Apply this rule to points O and G

O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )

G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )